What are the solutions to the equation 5x^2+20x=18x+720+2x ?

The solutions to the equation 5x^2+20x=18x+720+2x are x=12,x=-12

Find the zeros of 5x^2+20x=18x+720+2x

The zeros of 5x^2+20x=18x+720+2x are x=12,x=-12

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5 x^{2} + 20 x = 18 x + 720 + 2 x

x = 12, x = - 12

Solution steps

5 x^{2} + 20 x = 18 x + 720 + 2 x

Subtract

18 x + 2 x

from both sides

5 x^{2} + 20 x - (18 x + 2 x) = 18 x + 720 + 2 x - (18 x + 2 x)

Simplify

5 x^{2} = 720

Divide both sides by

5

x^{2} = 144

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 144, x = - 144

144 = 12

- 144 = - 12

x = 12, x = - 12

x, y = x^{2} - 1

x, y = x^{2} - 2

x (x + 7) = 690

2 x (3 x + 5) = - 1 + 4 x

\frac{1}{2} x^{2} - 4 x + 3

What are the solutions to the equation 5x^2+20x=18x+720+2x ?
The solutions to the equation 5x^2+20x=18x+720+2x are x=12,x=-12
Find the zeros of 5x^2+20x=18x+720+2x
The zeros of 5x^2+20x=18x+720+2x are x=12,x=-12