What are the solutions to the equation (10+2s)^2+(5+s)^2+2^2=9 ?

The solutions to the equation (10+2s)^2+(5+s)^2+2^2=9 are s=-4,s=-6

Find the zeros of (10+2s)^2+(5+s)^2+2^2=9

The zeros of (10+2s)^2+(5+s)^2+2^2=9 are s=-4,s=-6

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(10 + 2 s)^{2} + (5 + s)^{2} + 2^{2} = 9

s = - 4, s = - 6

Solution steps

(10 + 2 s)^{2} + (5 + s)^{2} + 2^{2} = 9

Expand

(10 + 2 s)^{2} + (5 + s)^{2} + 2^{2} : 5 s^{2} + 50 s + 129

5 s^{2} + 50 s + 129 = 9

Move

9

to the left side

5 s^{2} + 50 s + 120 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 5 \cdot 120}{2 \cdot 5}

5 0^{2} - 4 \cdot 5 \cdot 120 = 10

s_{1, 2} = \frac{- 50 \pm 10}{2 \cdot 5}

Separate the solutions

s_{1} = \frac{- 50 + 10}{2 \cdot 5}, s_{2} = \frac{- 50 - 10}{2 \cdot 5}

s = \frac{- 50 + 10}{2 \cdot 5} : - 4

s = \frac{- 50 - 10}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

s = - 4, s = - 6

2 x^{1} - x^{2} + 3 = 1

6 x^{2} - 4 x = 0

4^{2} + x^{2} = 1 1^{2}

3 y^{2} - 7 y = 3

5 n^{2} + 8 = 4

What are the solutions to the equation (10+2s)^2+(5+s)^2+2^2=9 ?
The solutions to the equation (10+2s)^2+(5+s)^2+2^2=9 are s=-4,s=-6
Find the zeros of (10+2s)^2+(5+s)^2+2^2=9
The zeros of (10+2s)^2+(5+s)^2+2^2=9 are s=-4,s=-6