What are the solutions to the equation 9x^2-2x+25=8x^2+8x ?

The solutions to the equation 9x^2-2x+25=8x^2+8x are x=5

Find the zeros of 9x^2-2x+25=8x^2+8x

The zeros of 9x^2-2x+25=8x^2+8x are x=5

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9 x^{2} - 2 x + 25 = 8 x^{2} + 8 x

x = 5

Solution steps

9 x^{2} - 2 x + 25 = 8 x^{2} + 8 x

Move

8 x

to the left side

9 x^{2} - 10 x + 25 = 8 x^{2}

Move

8 x^{2}

to the left side

x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

x = 5

The solution to the quadratic equation is:

x = 5

p^{2} - 14 p = 0

x^{2} + 1 x - 1 = 0

(r - 1) (r + 1) = 0

x, f x = x^{2} - 4 x

x - x^{2} = 5

What are the solutions to the equation 9x^2-2x+25=8x^2+8x ?
The solutions to the equation 9x^2-2x+25=8x^2+8x are x=5
Find the zeros of 9x^2-2x+25=8x^2+8x
The zeros of 9x^2-2x+25=8x^2+8x are x=5