What are the solutions to the equation (1/2)^2+x^2=1 ?

The solutions to the equation (1/2)^2+x^2=1 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2

Find the zeros of (1/2)^2+x^2=1

The zeros of (1/2)^2+x^2=1 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\frac{1}{2})^{2} + x^{2} = 1

x = \frac{3}{2}, x = - \frac{3}{2}

Solution steps

(\frac{1}{2})^{2} + x^{2} = 1

Expand

(\frac{1}{2})^{2} + x^{2} : \frac{1}{4} + x^{2}

\frac{1}{4} + x^{2} = 1

Move

\frac{1}{4}

to the right side

x^{2} = 1 - \frac{1}{4}

Simplify

1 - \frac{1}{4} : \frac{3}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{4}, x = - \frac{3}{4}

\frac{3}{4} = \frac{3}{2}

- \frac{3}{4} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

9 x^{2} - 4 x - 2 = 0

4 + x - 4 (1 - x) + 5 (2 + x) = 0

4 x (3 x - 7) = 5

\frac{w ^{2}}{8} - \frac{w}{2} - 4 = 0

196 - x^{2}

What are the solutions to the equation (1/2)^2+x^2=1 ?
The solutions to the equation (1/2)^2+x^2=1 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2
Find the zeros of (1/2)^2+x^2=1
The zeros of (1/2)^2+x^2=1 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2