What are the solutions to the equation 4x^1+2x^2=2,3x^1-6x^2=6 ?

The solutions to the equation 4x^1+2x^2=2,3x^1-6x^2=6 are x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of 4x^1+2x^2=2,3x^1-6x^2=6

The zeros of 4x^1+2x^2=2,3x^1-6x^2=6 are x=-1+sqrt(2),x=-1-sqrt(2)

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4 x^{1} + 2 x^{2} = 2, 3 x^{1} - 6 x^{2} = 6

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

4 x^{1} + 2 x^{2} = 2

Refine

4 x + 2 x^{2} = 2

Move

2

to the left side

4 x + 2 x^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 2) = 42

x_{1, 2} = \frac{- 4 \pm 4 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 4 2}{2 \cdot 2}, x_{2} = \frac{- 4 - 4 2}{2 \cdot 2}

x = \frac{- 4 + 4 2}{2 \cdot 2} : - 1 + 2

x = \frac{- 4 - 4 2}{2 \cdot 2} : - 1 - 2

The solutions to the quadratic equation are:

x = - 1 + 2, x = - 1 - 2

109 x^{2} - 3 x - 2 = 0

x, x^{2} + y^{2} - 6 x + 6 y + 18 = 0

x = 5 x - 4 x^{2} + 3

x^{2} + (m + 3) \cdot x + (m + 6) = 0

x, (y - 3 x) (x - 8 y) = 0

What are the solutions to the equation 4x^1+2x^2=2,3x^1-6x^2=6 ?
The solutions to the equation 4x^1+2x^2=2,3x^1-6x^2=6 are x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of 4x^1+2x^2=2,3x^1-6x^2=6
The zeros of 4x^1+2x^2=2,3x^1-6x^2=6 are x=-1+sqrt(2),x=-1-sqrt(2)