What is the answer to 2^x+2^{x+1}+2^{x+2}=448 ?

The answer to 2^x+2^{x+1}+2^{x+2}=448 is x=6

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2^x+2^{x+1}+2^{x+2}=448

2^{x} + 2^{x + 1} + 2^{x + 2} = 448

x = 6

Solution steps

2^{x} + 2^{x + 1} + 2^{x + 2} = 448

Factor

2^{x} + 2^{x + 1} + 2^{x + 2} : 7 \cdot 2^{x}

7 \cdot 2^{x} = 448

Divide both sides by

7

2^{x} = 64

Apply exponent rules

x = 6

\frac{3 ^{3 x - 2}}{( 3 ^{x + 3} )} = 81

4^{x + 1} + 4^{1 - x} = 10

21 \cdot 3^{x} - 2^{x + 3} = 3^{x + 1}

5^{2 x - 1} = 2 5^{x - 1}

(2. 1^{- 8})^{3} = 80. 1^{a}

What is the answer to 2^x+2^{x+1}+2^{x+2}=448 ?
The answer to 2^x+2^{x+1}+2^{x+2}=448 is x=6
Solve for x: 2^x+2^{x+1}+2^{x+2}=448
The solution is x=6