What is the answer to solvefor x,((9^{x-1}))/((3^{y+2))}=81 ?

The answer to solvefor x,((9^{x-1}))/((3^{y+2))}=81 is x=(y+6)/2+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,((9^{x-1}))/((3^{y+2))}=81

solve for

x, \frac{( 9 ^{x - 1} )}{( 3 ^{y + 2} )} = 81

x = \frac{y + 6}{2} + 1

Solution steps

\frac{( 9 ^{x - 1} )}{( 3 ^{y + 2} )} = 81

Apply exponent rules

2 (x - 1) = y + 6

Solve

2 (x - 1) = y + 6 : x = \frac{y + 6}{2} + 1

x = \frac{y + 6}{2} + 1

1 6^{x} + 2 0^{x} + 2 5^{x} = 0

3 2^{x} = 8

(\frac{1}{9})^{6 x + 1} = 9^{7 - x}

x, y^{x} - y^{y} = - 26

x^{(l o g_{10} (x)) + 2} = 1 0^{(l o g_{10} (x)) + 2}

What is the answer to solvefor x,((9^{x-1}))/((3^{y+2))}=81 ?
The answer to solvefor x,((9^{x-1}))/((3^{y+2))}=81 is x=(y+6)/2+1