What is the answer to solvefor x,r+s-2t=sqrt(2x+y) ?

The answer to solvefor x,r+s-2t=sqrt(2x+y) is x=(2rs-4rt+r^2+s^2-4st+4t^2-y)/2

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solvefor x,r+s-2t=sqrt(2x+y)

solve for

x, r + s - 2 t = 2 x + y

x = \frac{2 rs - 4 r t + r ^{2} + s ^{2} - 4 s t + 4 t ^{2} - y}{2}

Solution steps

r + s - 2 t = 2 x + y

Square both sides:

2 rs - 4 r t + r^{2} + s^{2} - 4 s t + 4 t^{2} = 2 x + y

2 rs - 4 r t + r^{2} + s^{2} - 4 s t + 4 t^{2} = 2 x + y

Solve

2 rs - 4 r t + r^{2} + s^{2} - 4 s t + 4 t^{2} = 2 x + y : x = \frac{2 rs - 4 r t + r ^{2} + s ^{2} - 4 s t + 4 t ^{2} - y}{2}

x = \frac{2 rs - 4 r t + r ^{2} + s ^{2} - 4 s t + 4 t ^{2} - y}{2}

\frac{1}{( 1 + x ^{2} )} = \frac{1}{( 2 )}

4 x^{3} - 3 x^{2.5} - 3 x + 9 = 15

x + x^{\frac{1}{2}} = 20

(x^{2} - 16) \cdot 3 - x = 0

x + a + x = \frac{( 3 a )}{( a + x )}

What is the answer to solvefor x,r+s-2t=sqrt(2x+y) ?
The answer to solvefor x,r+s-2t=sqrt(2x+y) is x=(2rs-4rt+r^2+s^2-4st+4t^2-y)/2