What is the answer to (x^2-16)*sqrt(3-x)=0 ?

The answer to (x^2-16)*sqrt(3-x)=0 is x=3,x=-4

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(x^2-16)*sqrt(3-x)=0

(x^{2} - 16) \cdot 3 - x = 0

x = 3, x = - 4

Solution steps

(x^{2} - 16) 3 - x = 0

Factor

(x^{2} - 16) 3 - x : 3 - x (x + 4) (x - 4)

3 - x (x + 4) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 - x = 0 or x + 4 = 0 or x - 4 = 0

Solve

3 - x = 0 : x = 3

Solve

x + 4 = 0 : x = - 4

Solve

x - 4 = 0 : x = 4

x = 3, x = - 4, x = 4

Verify Solutions:

x = 3

True

, x = - 4

True

, x = 4

False

The solutions are

x = 3, x = - 4

x + a + x = \frac{( 3 a )}{( a + x )}

v, 5 w = \frac{( ( v + 2 ) ^{\frac{1}{2}} )}{3}

x, z = x y + y \cdot x^{2} - a^{2} + b

x^{2} + (x - 1)^{2} = 1

(2 x + 5)^{\frac{1}{3}} = 5

What is the answer to (x^2-16)*sqrt(3-x)=0 ?
The answer to (x^2-16)*sqrt(3-x)=0 is x=3,x=-4
Solve for x: (x^2-16)*sqrt(3-x)=0
The solution is x=3,x=-4