What is the answer to 1/((sqrt(1+x^2)))= 1/((sqrt(2))) ?

The answer to 1/((sqrt(1+x^2)))= 1/((sqrt(2))) is x=1,x=-1

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1/((sqrt(1+x^2)))= 1/((sqrt(2)))

\frac{1}{( 1 + x ^{2} )} = \frac{1}{( 2 )}

x = 1, x = - 1

Solution steps

\frac{1}{( 1 + x ^{2} )} = \frac{1}{( 2 )}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

1 \cdot 2 = 1 + x^{2} \cdot 1

Expand

1 + x^{2} \cdot 1 : 1 + x^{2}

1 \cdot 2 = 1 + x^{2}

Square both sides:

2 = 1 + x^{2}

2 = 1 + x^{2}

Solve

2 = 1 + x^{2} : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions:

x = 1

True

, x = - 1

True

The solutions are

x = 1, x = - 1

4 x^{3} - 3 x^{2.5} - 3 x + 9 = 15

x + x^{\frac{1}{2}} = 20

(x^{2} - 16) \cdot 3 - x = 0

x + a + x = \frac{( 3 a )}{( a + x )}

v, 5 w = \frac{( ( v + 2 ) ^{\frac{1}{2}} )}{3}

What is the answer to 1/((sqrt(1+x^2)))= 1/((sqrt(2))) ?
The answer to 1/((sqrt(1+x^2)))= 1/((sqrt(2))) is x=1,x=-1
Solve for x: 1/((sqrt(1+x^2)))= 1/((sqrt(2)))
The solution is x=1,x=-1