What is the answer to log_{4}(3x-1)=log_{4}(x) ?

The answer to log_{4}(3x-1)=log_{4}(x) is x= 1/2

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log_{4}(3x-1)=log_{4}(x)

lo g_{4} (3 x - 1) = lo g_{4} (x)

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

lo g_{4} (3 x - 1) = lo g_{4} (x)

Apply log rules

3 x - 1 = x

Solve

3 x - 1 = x : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

lo g_{3} (x) = lo g_{3} (+ 5)

lo g_{10} (x + 5) + lo g_{10} (x - 4) = lo g_{10} (10)

lo g_{2} (4 x + 5) = lo g_{2} (9 - 2 x)

ln (x - 2) = x + 1

lo g_{10} (8 x) = \frac{11}{16}

What is the answer to log_{4}(3x-1)=log_{4}(x) ?
The answer to log_{4}(3x-1)=log_{4}(x) is x= 1/2
Solve for x: log_{4}(3x-1)=log_{4}(x)
The solution is x= 1/2