What is 2x-3y=7,(a+b)x-(a+b-3)y=4a+b ?

The solution to 2x-3y=7,(a+b)x-(a+b-3)y=4a+b is No Solution

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2x-3y=7,(a+b)x-(a+b-3)y=4a+b

2 x - 3 y = 7, (a + b) x - (a + b - 3) y = 4 a + b

No Solution

Solution steps

[2 x - 3 y = 7 (a + b) x - (a + b - 3) y = 4 a + b]

Isolate

x

for

2 x - 3 y = 7 : x = \frac{7 + 3 y}{2}

Plug the solutions

x = \frac{7 + 3 y}{2}

into

(a + b) x - (a + b - 3) y = 4 a + b

For

(a + b) x - (a + b - 3) y = 4 a + b

, subsitute

x

with

\frac{7 + 3 y}{2} : y = \frac{a - 5 b}{a + b + 6}; a \neq = - b - 6

Plug the solutions

y = \frac{a - 5 b}{a + b + 6}

into

2 x - 3 y = 7

For

2 x - 3 y = 7

, subsitute

y

with

\frac{a - 5 b}{a + b + 6} : x = \frac{5 a - 4 b + 21}{a + b + 6}

Verify solutions by plugging them into the original equations

No Solution

3 a + 2 = 3, b + 4 = 3 c + 5

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}, \frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

f (x) (x)^{1} (x) = 1, + x f (x) (x)^{2} (x) = x^{2}

x + 3 y = 13, x^{2} + 3 y^{2} = 43

u (y, x) - 9 u (y, x) = (\frac{1}{2}) x^{4}, y = 6

What is 2x-3y=7,(a+b)x-(a+b-3)y=4a+b ?
The solution to 2x-3y=7,(a+b)x-(a+b-3)y=4a+b is No Solution