What is x+y=10,log_{2}(x)+log_{2}(y)=4 ?

The solution to x+y=10,log_{2}(x)+log_{2}(y)=4 is

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x+y=10,log_{2}(x)+log_{2}(y)=4

x + y = 10, lo g_{2} (x) + lo g_{2} (y) = 4

(x = 8, x = 2, y = 2 y = 8)

Solution steps

[x + y = 10 lo g_{2} (x) + lo g_{2} (y) = 4]

Isolate

x

for

x + y = 10 : x = 10 - y

Plug the solutions

x = 10 - y

into

lo g_{2} (x) + lo g_{2} (y) = 4

For

lo g_{2} (x) + lo g_{2} (y) = 4

, subsitute

x

with

10 - y : y = 2, y = 8

Plug the solutions

y = 2, y = 8

into

x + y = 10

For

x + y = 10

, subsitute

y

with

2 : x = 8

For

x + y = 10

, subsitute

y

with

8 : x = 2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x + y = 10, lo g_{2} (x) + lo g_{2} (y) = 4

are

(x = 8, x = 2, y = 2 y = 8)

5 x^{2} - 27 x^{2} + 36 = 0, y^{2} y + 2 = 0

f (x) = 2, x^{2} + 8 x - 3 x^{0} = - 3

2 x^{3} y = 1, 0.93 x y = 1.1

8 x^{4} - 3 y = 17, 7 x - 4 y = 8

x - y = - 6, x^{2} - y = - 4

What is x+y=10,log_{2}(x)+log_{2}(y)=4 ?
The solution to x+y=10,log_{2}(x)+log_{2}(y)=4 is