What are the solutions to the equation x^3+12x^2+48x+64=0 ?

The solutions to the equation x^3+12x^2+48x+64=0 are x=-4

Find the zeros of x^3+12x^2+48x+64=0

The zeros of x^3+12x^2+48x+64=0 are x=-4

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x^{3} + 12 x^{2} + 48 x + 64 = 0

x = - 4

Solution steps

x^{3} + 12 x^{2} + 48 x + 64 = 0

Factor

x^{3} + 12 x^{2} + 48 x + 64 : (x + 4)^{3}

(x + 4)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0

Solve

x + 4 = 0 : x = - 4

The solution is

x = - 4

x^{2} + 18 x + 71 = 0

∣ x + 3 ∣ \leq 4

3 x^{2} - 10 x - 7 = 0

\frac{( \frac{1}{4} )}{2}

∣ 4 x - 5 ∣ \leq 12

What are the solutions to the equation x^3+12x^2+48x+64=0 ?
The solutions to the equation x^3+12x^2+48x+64=0 are x=-4
Find the zeros of x^3+12x^2+48x+64=0
The zeros of x^3+12x^2+48x+64=0 are x=-4