What is expand L(x)(y^4-y=sinh(x)) ?

The solution to expand L(x)(y^4-y=sinh(x)) is L(x)y^4-L(x)y=sinh(x)

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expand L(x)(y^4-y=sinh(x))

expand

L (x) (y^{4} - y = sinh (x))

L (x) y^{4} - L (x) y = sinh (x)

Solution steps

L (x) (y^{4} - y = sinh (x))

= L (x) (y^{4} - = sinh (x) y)

Apply the distributive law:

a (b - c) = ab - a c

a = L (x), b = y^{4}, c = y = sinh (x)

L (x) y^{4} - L (x) y = sinh (x)

(3 y d x + 6 d x - x d y = 0) \frac{1}{y d y}

\frac{( x + 4 ) ( 6 x - 1 )}{6}

\frac{1}{( x + h + 5 ) ^{2}}

e^{2 t - 10} h (t - 5)

π^{e^{- 1}} - arccos (- 1)

What is expand L(x)(y^4-y=sinh(x)) ?
The solution to expand L(x)(y^4-y=sinh(x)) is L(x)y^4-L(x)y=sinh(x)