What is expand (j(x)=9,x-5*h(x)=-2x)(x) ?

The solution to expand (j(x)=9,x-5*h(x)=-2x)(x) is jx^2=-2x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (j(x)=9,x-5*h(x)=-2x)(x)

expand

(j (x) = 9, x - 5 \cdot h (x) = - 2 x) (x)

j x^{2} = - 2 x^{2}

Solution steps

(j (x) = 9, x - 5 h (x) = - 2 x) (x)

= (x) (9 =, j (x) x - 5 = h (x) - 2 x)

Distribute parentheses

(x) j (x) = 9, x + (x) (- 5 h (x) =) + (x) (- 2 x)

Apply minus-plus rules

+ (- a) = - a

j (x) (x) = 9, x - 5 (x) h (x) = - 2 (x) x

Simplify

j (x) (x) = 9, x - 5 (x) h (x) = - 2 (x) x : j x^{2} = - 2 x^{2}

j x^{2} = - 2 x^{2}

\frac{( 40 x + 1 ) ( 40 x - 1 )}{25}

\frac{x ^{3} ( 3 ln ( x ) - 1 )}{9}

- \frac{3 ( b ^{2} + b + 6 )}{2}

\frac{5 ( - x + 4 )}{x ^{3}}

(\frac{- 20 - 2 y}{7})^{2}

What is expand (j(x)=9,x-5*h(x)=-2x)(x) ?
The solution to expand (j(x)=9,x-5*h(x)=-2x)(x) is jx^2=-2x^2