What are the solutions to the equation a^2+4a=0 ?

The solutions to the equation a^2+4a=0 are a=0,a=-4

Find the zeros of a^2+4a=0

The zeros of a^2+4a=0 are a=0,a=-4

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a^{2} + 4 a = 0

a = 0, a = - 4

Solution steps

a^{2} + 4 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

a_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 4 + 4}{2 \cdot 1}, a_{2} = \frac{- 4 - 4}{2 \cdot 1}

a = \frac{- 4 + 4}{2 \cdot 1} : 0

a = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

a = 0, a = - 4

\frac{- 2 x ^{2} - 20 x - 50}{x ^{2} + 4} \geq 0

6 x^{2} - 9 x = - 1

3 x^{2} - 26 x + 35 = 0

- - 36

3 (x - 2) 2 - 37 = 20

What are the solutions to the equation a^2+4a=0 ?
The solutions to the equation a^2+4a=0 are a=0,a=-4
Find the zeros of a^2+4a=0
The zeros of a^2+4a=0 are a=0,a=-4