What are the solutions to the equation 3(x+4)^2=8 ?

The solutions to the equation 3(x+4)^2=8 are x=(2sqrt(2))/(sqrt(3))-4,x=-(2sqrt(2))/(sqrt(3))-4

Find the zeros of 3(x+4)^2=8

The zeros of 3(x+4)^2=8 are x=(2sqrt(2))/(sqrt(3))-4,x=-(2sqrt(2))/(sqrt(3))-4

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3 (x + 4)^{2} = 8

x = \frac{2 2}{3} - 4, x = - \frac{2 2}{3} - 4

Decimal Notation

x = - 2.36700 \dots, x = - 5.63299 \dots

Solution steps

3 (x + 4)^{2} = 8

Divide both sides by

3

(x + 4)^{2} = \frac{8}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = \frac{8}{3} : x = \frac{2 2}{3} - 4

Solve

x + 4 = - \frac{8}{3} : x = - \frac{2 2}{3} - 4

The solutions to the quadratic equation are:

x = \frac{2 2}{3} - 4, x = - \frac{2 2}{3} - 4

- 4 + 16 x - 15 x^{2} = 0

4 x^{2} - 20 x + 29 = 0

(x + 5)^{2} + 5 (2 x + 3) = 2 (x + 4)^{2}

4 x^{2} + 40 x + 100 = 0

x^{2} - 8 x + 96 = 0

What are the solutions to the equation 3(x+4)^2=8 ?
The solutions to the equation 3(x+4)^2=8 are x=(2sqrt(2))/(sqrt(3))-4,x=-(2sqrt(2))/(sqrt(3))-4
Find the zeros of 3(x+4)^2=8
The zeros of 3(x+4)^2=8 are x=(2sqrt(2))/(sqrt(3))-4,x=-(2sqrt(2))/(sqrt(3))-4