What are the solutions to the equation 9x^2-18x+3=0 ?

The solutions to the equation 9x^2-18x+3=0 are x=(3+sqrt(6))/3 ,x=(3-sqrt(6))/3

Find the zeros of 9x^2-18x+3=0

The zeros of 9x^2-18x+3=0 are x=(3+sqrt(6))/3 ,x=(3-sqrt(6))/3

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9 x^{2} - 18 x + 3 = 0

x = \frac{3 + 6}{3}, x = \frac{3 - 6}{3}

Solution steps

9 x^{2} - 18 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 3}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 \cdot 3 = 66

x_{1, 2} = \frac{- ( - 18 ) \pm 6 6}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 6}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 6 6}{2 \cdot 9}

x = \frac{- ( - 18 ) + 6 6}{2 \cdot 9} : \frac{3 + 6}{3}

x = \frac{- ( - 18 ) - 6 6}{2 \cdot 9} : \frac{3 - 6}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 6}{3}, x = \frac{3 - 6}{3}

- x^{2} + 4 x - 96 = 0

2 (5 x + 2)^{2} = 64

x^{2} + 4 b = 0, b > 0

x^{2} - 7 x + \frac{5}{4} = 0

3 q^{2} - 105 q + 750 = 0

What are the solutions to the equation 9x^2-18x+3=0 ?
The solutions to the equation 9x^2-18x+3=0 are x=(3+sqrt(6))/3 ,x=(3-sqrt(6))/3
Find the zeros of 9x^2-18x+3=0
The zeros of 9x^2-18x+3=0 are x=(3+sqrt(6))/3 ,x=(3-sqrt(6))/3