What are the solutions to the equation 2(3x+1)^2-8=0 ?

The solutions to the equation 2(3x+1)^2-8=0 are x= 1/3 ,x=-1

Find the zeros of 2(3x+1)^2-8=0

The zeros of 2(3x+1)^2-8=0 are x= 1/3 ,x=-1

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2 (3 x + 1)^{2} - 8 = 0

x = \frac{1}{3}, x = - 1

Solution steps

2 (3 x + 1)^{2} - 8 = 0

Move

8

to the right side

2 (3 x + 1)^{2} = 8

Divide both sides by

2

(3 x + 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 1 = 4 : x = \frac{1}{3}

Solve

3 x + 1 = - 4 : x = - 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 1

9 x^{2} - 18 x + 3 = 0

- x^{2} + 4 x - 96 = 0

2 (5 x + 2)^{2} = 64

x^{2} + 4 b = 0, b > 0

x^{2} - 7 x + \frac{5}{4} = 0

What are the solutions to the equation 2(3x+1)^2-8=0 ?
The solutions to the equation 2(3x+1)^2-8=0 are x= 1/3 ,x=-1
Find the zeros of 2(3x+1)^2-8=0
The zeros of 2(3x+1)^2-8=0 are x= 1/3 ,x=-1