What are the solutions to the equation 3x+x^2-10=5 ?

The solutions to the equation 3x+x^2-10=5 are x=(-3+sqrt(69))/2 ,x=(-3-sqrt(69))/2

Find the zeros of 3x+x^2-10=5

The zeros of 3x+x^2-10=5 are x=(-3+sqrt(69))/2 ,x=(-3-sqrt(69))/2

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3 x + x^{2} - 10 = 5

x = \frac{- 3 + 69}{2}, x = \frac{- 3 - 69}{2}

Solution steps

3 x + x^{2} - 10 = 5

Move

5

to the left side

x^{2} + 3 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 15) = 69

x_{1, 2} = \frac{- 3 \pm 69}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 69}{2 \cdot 1}, x_{2} = \frac{- 3 - 69}{2 \cdot 1}

x = \frac{- 3 + 69}{2 \cdot 1} : \frac{- 3 + 69}{2}

x = \frac{- 3 - 69}{2 \cdot 1} : \frac{- 3 - 69}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 69}{2}, x = \frac{- 3 - 69}{2}

9 a = 16 - a^{2}

x, 3 x^{2} + m x - 4 = 0

n^{2} - 3 n + 10 = 0

10 x^{2} - 6 x + 4 = 0

4 x^{2} - 7 = 3 x

What are the solutions to the equation 3x+x^2-10=5 ?
The solutions to the equation 3x+x^2-10=5 are x=(-3+sqrt(69))/2 ,x=(-3-sqrt(69))/2
Find the zeros of 3x+x^2-10=5
The zeros of 3x+x^2-10=5 are x=(-3+sqrt(69))/2 ,x=(-3-sqrt(69))/2