What are the solutions to the equation 9a=16-a^2 ?

The solutions to the equation 9a=16-a^2 are a=-(9+sqrt(145))/2 ,a=(sqrt(145)-9)/2

Find the zeros of 9a=16-a^2

The zeros of 9a=16-a^2 are a=-(9+sqrt(145))/2 ,a=(sqrt(145)-9)/2

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9 a = 16 - a^{2}

a = - \frac{9 + 145}{2}, a = \frac{145 - 9}{2}

Solution steps

9 a = 16 - a^{2}

Switch sides

16 - a^{2} = 9 a

Move

9 a

to the left side

16 - a^{2} - 9 a = 0

Write in the standard form

a x^{2} + b x + c = 0

- a^{2} - 9 a + 16 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 1 ) \cdot 16}{2 ( - 1 )}

(- 9)^{2} - 4 (- 1) \cdot 16 = 145

a_{1, 2} = \frac{- ( - 9 ) \pm 145}{2 ( - 1 )}

Separate the solutions

a_{1} = \frac{- ( - 9 ) + 145}{2 ( - 1 )}, a_{2} = \frac{- ( - 9 ) - 145}{2 ( - 1 )}

a = \frac{- ( - 9 ) + 145}{2 ( - 1 )} : - \frac{9 + 145}{2}

a = \frac{- ( - 9 ) - 145}{2 ( - 1 )} : \frac{145 - 9}{2}

The solutions to the quadratic equation are:

a = - \frac{9 + 145}{2}, a = \frac{145 - 9}{2}

x, 3 x^{2} + m x - 4 = 0

n^{2} - 3 n + 10 = 0

10 x^{2} - 6 x + 4 = 0

4 x^{2} - 7 = 3 x

(s - 4)^{2} - 81 = 0

What are the solutions to the equation 9a=16-a^2 ?
The solutions to the equation 9a=16-a^2 are a=-(9+sqrt(145))/2 ,a=(sqrt(145)-9)/2
Find the zeros of 9a=16-a^2
The zeros of 9a=16-a^2 are a=-(9+sqrt(145))/2 ,a=(sqrt(145)-9)/2