What are the solutions to the equation 10x^2-6x+4=0 ?

The solutions to the equation 10x^2-6x+4=0 are x= 3/10+i(sqrt(31))/(10),x= 3/10-i(sqrt(31))/(10)

Find the zeros of 10x^2-6x+4=0

The zeros of 10x^2-6x+4=0 are x= 3/10+i(sqrt(31))/(10),x= 3/10-i(sqrt(31))/(10)

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10 x^{2} - 6 x + 4 = 0

x = \frac{3}{10} + i \frac{31}{10}, x = \frac{3}{10} - i \frac{31}{10}

Solution steps

10 x^{2} - 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 10 \cdot 4}{2 \cdot 10}

Simplify

(- 6)^{2} - 4 \cdot 10 \cdot 4 : 231 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 31 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 31 i}{2 \cdot 10}, x_{2} = \frac{- ( - 6 ) - 2 31 i}{2 \cdot 10}

x = \frac{- ( - 6 ) + 2 31 i}{2 \cdot 10} : \frac{3}{10} + i \frac{31}{10}

x = \frac{- ( - 6 ) - 2 31 i}{2 \cdot 10} : \frac{3}{10} - i \frac{31}{10}

The solutions to the quadratic equation are:

x = \frac{3}{10} + i \frac{31}{10}, x = \frac{3}{10} - i \frac{31}{10}

4 x^{2} - 7 = 3 x

(s - 4)^{2} - 81 = 0

3 (3 x - 1)^{2} = 21

(4 x - 1)^{2} = 196

2 x (4 x + 5) = - 3

What are the solutions to the equation 10x^2-6x+4=0 ?
The solutions to the equation 10x^2-6x+4=0 are x= 3/10+i(sqrt(31))/(10),x= 3/10-i(sqrt(31))/(10)
Find the zeros of 10x^2-6x+4=0
The zeros of 10x^2-6x+4=0 are x= 3/10+i(sqrt(31))/(10),x= 3/10-i(sqrt(31))/(10)