What are the solutions to the equation n^2-3n+10=0 ?

The solutions to the equation n^2-3n+10=0 are n= 3/2+i(sqrt(31))/2 ,n= 3/2-i(sqrt(31))/2

Find the zeros of n^2-3n+10=0

The zeros of n^2-3n+10=0 are n= 3/2+i(sqrt(31))/2 ,n= 3/2-i(sqrt(31))/2

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n^{2} - 3 n + 10 = 0

n = \frac{3}{2} + i \frac{31}{2}, n = \frac{3}{2} - i \frac{31}{2}

Solution steps

n^{2} - 3 n + 10 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 10 : 31 i

n_{1, 2} = \frac{- ( - 3 ) \pm 31 i}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 31 i}{2 \cdot 1}, n_{2} = \frac{- ( - 3 ) - 31 i}{2 \cdot 1}

n = \frac{- ( - 3 ) + 31 i}{2 \cdot 1} : \frac{3}{2} + i \frac{31}{2}

n = \frac{- ( - 3 ) - 31 i}{2 \cdot 1} : \frac{3}{2} - i \frac{31}{2}

The solutions to the quadratic equation are:

n = \frac{3}{2} + i \frac{31}{2}, n = \frac{3}{2} - i \frac{31}{2}

10 x^{2} - 6 x + 4 = 0

4 x^{2} - 7 = 3 x

(s - 4)^{2} - 81 = 0

3 (3 x - 1)^{2} = 21

(4 x - 1)^{2} = 196

What are the solutions to the equation n^2-3n+10=0 ?
The solutions to the equation n^2-3n+10=0 are n= 3/2+i(sqrt(31))/2 ,n= 3/2-i(sqrt(31))/2
Find the zeros of n^2-3n+10=0
The zeros of n^2-3n+10=0 are n= 3/2+i(sqrt(31))/2 ,n= 3/2-i(sqrt(31))/2