What are the solutions to the equation (s-4)^2-81=0 ?

The solutions to the equation (s-4)^2-81=0 are s=13,s=-5

Find the zeros of (s-4)^2-81=0

The zeros of (s-4)^2-81=0 are s=13,s=-5

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(s - 4)^{2} - 81 = 0

s = 13, s = - 5

Solution steps

(s - 4)^{2} - 81 = 0

Move

81

to the right side

(s - 4)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

s - 4 = 81 : s = 13

Solve

s - 4 = - 81 : s = - 5

The solutions to the quadratic equation are:

s = 13, s = - 5

3 (3 x - 1)^{2} = 21

(4 x - 1)^{2} = 196

2 x (4 x + 5) = - 3

5 x^{2} + 4 x + 7 = 0

x^{2} - 82 x + 1681 = 0

What are the solutions to the equation (s-4)^2-81=0 ?
The solutions to the equation (s-4)^2-81=0 are s=13,s=-5
Find the zeros of (s-4)^2-81=0
The zeros of (s-4)^2-81=0 are s=13,s=-5