What are the solutions to the equation x^2+2x+1=5x+6 ?

The solutions to the equation x^2+2x+1=5x+6 are x=(3+sqrt(29))/2 ,x=(3-sqrt(29))/2

Find the zeros of x^2+2x+1=5x+6

The zeros of x^2+2x+1=5x+6 are x=(3+sqrt(29))/2 ,x=(3-sqrt(29))/2

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x^{2} + 2 x + 1 = 5 x + 6

x = \frac{3 + 29}{2}, x = \frac{3 - 29}{2}

Solution steps

x^{2} + 2 x + 1 = 5 x + 6

Move

6

to the left side

x^{2} + 2 x - 5 = 5 x

Move

5 x

to the left side

x^{2} - 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 5) = 29

x_{1, 2} = \frac{- ( - 3 ) \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 29}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 29}{2 \cdot 1}

x = \frac{- ( - 3 ) + 29}{2 \cdot 1} : \frac{3 + 29}{2}

x = \frac{- ( - 3 ) - 29}{2 \cdot 1} : \frac{3 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 29}{2}, x = \frac{3 - 29}{2}

(x + 5) (x + 3) = 5 x + 25

9 x^{2} + 5 x + 10 = 0

(x + 6)^{2} = 12 x

(5 x + 4) (5 x - 4) = 0

9 (x - 1)^{2} + 7 = 0

What are the solutions to the equation x^2+2x+1=5x+6 ?
The solutions to the equation x^2+2x+1=5x+6 are x=(3+sqrt(29))/2 ,x=(3-sqrt(29))/2
Find the zeros of x^2+2x+1=5x+6
The zeros of x^2+2x+1=5x+6 are x=(3+sqrt(29))/2 ,x=(3-sqrt(29))/2