What are the solutions to the equation -8x^2+48x+576=0 ?

The solutions to the equation -8x^2+48x+576=0 are x=-6,x=12

Find the zeros of -8x^2+48x+576=0

The zeros of -8x^2+48x+576=0 are x=-6,x=12

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- 8 x^{2} + 48 x + 576 = 0

x = - 6, x = 12

Solution steps

- 8 x^{2} + 48 x + 576 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 ( - 8 ) \cdot 576}{2 ( - 8 )}

4 8^{2} - 4 (- 8) \cdot 576 = 144

x_{1, 2} = \frac{- 48 \pm 144}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 48 + 144}{2 ( - 8 )}, x_{2} = \frac{- 48 - 144}{2 ( - 8 )}

x = \frac{- 48 + 144}{2 ( - 8 )} : - 6

x = \frac{- 48 - 144}{2 ( - 8 )} : 12

The solutions to the quadratic equation are:

x = - 6, x = 12

x^{2} + 82 x + 1681 = 0

x^{2} + 5 x + 2 = - 4

- x^{2} - 5 x + 25 = - 2 x^{2} + 5 x

16 x^{2} - 24 x + 7 = 0

(w - 8) (w + 5) = 14

What are the solutions to the equation -8x^2+48x+576=0 ?
The solutions to the equation -8x^2+48x+576=0 are x=-6,x=12
Find the zeros of -8x^2+48x+576=0
The zeros of -8x^2+48x+576=0 are x=-6,x=12