What are the solutions to the equation 0.2x^2-1.1x-1=0 ?

The solutions to the equation 0.2x^2-1.1x-1=0 are x=(11+sqrt(201))/4 ,x=(11-sqrt(201))/4

Find the zeros of 0.2x^2-1.1x-1=0

The zeros of 0.2x^2-1.1x-1=0 are x=(11+sqrt(201))/4 ,x=(11-sqrt(201))/4

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0.2 x^{2} - 1.1 x - 1 = 0

x = \frac{11 + 201}{4}, x = \frac{11 - 201}{4}

Solution steps

0.2 x^{2} - 1.1 x - 1 = 0

Multiply both sides by

10

2 x^{2} - 11 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 10) = 201

x_{1, 2} = \frac{- ( - 11 ) \pm 201}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 201}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 201}{2 \cdot 2}

x = \frac{- ( - 11 ) + 201}{2 \cdot 2} : \frac{11 + 201}{4}

x = \frac{- ( - 11 ) - 201}{2 \cdot 2} : \frac{11 - 201}{4}

The solutions to the quadratic equation are:

x = \frac{11 + 201}{4}, x = \frac{11 - 201}{4}

n^{2} + 10 = 7 n

2 x^{2} - 6 x + c = 0

15 a x^{2} + 6 x - 3 a x = 0

x^{2} - 3 x - 8 = x + 4

3 x (1 - 2 x) = 16

What are the solutions to the equation 0.2x^2-1.1x-1=0 ?
The solutions to the equation 0.2x^2-1.1x-1=0 are x=(11+sqrt(201))/4 ,x=(11-sqrt(201))/4
Find the zeros of 0.2x^2-1.1x-1=0
The zeros of 0.2x^2-1.1x-1=0 are x=(11+sqrt(201))/4 ,x=(11-sqrt(201))/4