What are the solutions to the equation -7=2x^2-5 ?

The solutions to the equation -7=2x^2-5 are x=i,x=-i

Find the zeros of -7=2x^2-5

The zeros of -7=2x^2-5 are x=i,x=-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 7 = 2 x^{2} - 5

x = i, x = - i

Solution steps

- 7 = 2 x^{2} - 5

Switch sides

2 x^{2} - 5 = - 7

Move

5

to the right side

2 x^{2} = - 2

Divide both sides by

2

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

- 2 x^{2} - 5 x + 27 = 0

0.2 x^{2} - 0.4 x - 15 = 0

x = 2 x^{2} + 5

- 0.2 x^{2} - 0.3 x + 1 = 0

- x^{2} - x = - 4

What are the solutions to the equation -7=2x^2-5 ?
The solutions to the equation -7=2x^2-5 are x=i,x=-i
Find the zeros of -7=2x^2-5
The zeros of -7=2x^2-5 are x=i,x=-i