What are the solutions to the equation 0.2x^2-0.4x-15=0 ?

The solutions to the equation 0.2x^2-0.4x-15=0 are x=1+2sqrt(19),x=1-2sqrt(19)

Find the zeros of 0.2x^2-0.4x-15=0

The zeros of 0.2x^2-0.4x-15=0 are x=1+2sqrt(19),x=1-2sqrt(19)

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0.2 x^{2} - 0.4 x - 15 = 0

x = 1 + 219, x = 1 - 219

Solution steps

0.2 x^{2} - 0.4 x - 15 = 0

Multiply both sides by

10

2 x^{2} - 4 x - 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 150 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 150) = 819

x_{1, 2} = \frac{- ( - 4 ) \pm 8 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 19}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 8 19}{2 \cdot 2}

x = \frac{- ( - 4 ) + 8 19}{2 \cdot 2} : 1 + 219

x = \frac{- ( - 4 ) - 8 19}{2 \cdot 2} : 1 - 219

The solutions to the quadratic equation are:

x = 1 + 219, x = 1 - 219

x = 2 x^{2} + 5

- 0.2 x^{2} - 0.3 x + 1 = 0

- x^{2} - x = - 4

x (x + 7) = 14

(2 x + 1)^{2} - (x + 2) = x (x + 2) + 3

What are the solutions to the equation 0.2x^2-0.4x-15=0 ?
The solutions to the equation 0.2x^2-0.4x-15=0 are x=1+2sqrt(19),x=1-2sqrt(19)
Find the zeros of 0.2x^2-0.4x-15=0
The zeros of 0.2x^2-0.4x-15=0 are x=1+2sqrt(19),x=1-2sqrt(19)