What are the solutions to the equation -0.2x^2-0.3x+1=0 ?

The solutions to the equation -0.2x^2-0.3x+1=0 are x=-(3+sqrt(89))/4 ,x=(sqrt(89)-3)/4

Find the zeros of -0.2x^2-0.3x+1=0

The zeros of -0.2x^2-0.3x+1=0 are x=-(3+sqrt(89))/4 ,x=(sqrt(89)-3)/4

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- 0.2 x^{2} - 0.3 x + 1 = 0

x = - \frac{3 + 89}{4}, x = \frac{89 - 3}{4}

Decimal Notation

x = - 3.10849 \dots, x = 1.60849 \dots

Solution steps

- 0.2 x^{2} - 0.3 x + 1 = 0

Multiply both sides by

10

- 2 x^{2} - 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 2 ) \cdot 10}{2 ( - 2 )}

(- 3)^{2} - 4 (- 2) \cdot 10 = 89

x_{1, 2} = \frac{- ( - 3 ) \pm 89}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 89}{2 ( - 2 )}, x_{2} = \frac{- ( - 3 ) - 89}{2 ( - 2 )}

x = \frac{- ( - 3 ) + 89}{2 ( - 2 )} : - \frac{3 + 89}{4}

x = \frac{- ( - 3 ) - 89}{2 ( - 2 )} : \frac{89 - 3}{4}

The solutions to the quadratic equation are:

x = - \frac{3 + 89}{4}, x = \frac{89 - 3}{4}

- x^{2} - x = - 4

x (x + 7) = 14

(2 x + 1)^{2} - (x + 2) = x (x + 2) + 3

(x + 8)^{2} = - x - 2

3 x^{2} + 7 x - 6 = 0

What are the solutions to the equation -0.2x^2-0.3x+1=0 ?
The solutions to the equation -0.2x^2-0.3x+1=0 are x=-(3+sqrt(89))/4 ,x=(sqrt(89)-3)/4
Find the zeros of -0.2x^2-0.3x+1=0
The zeros of -0.2x^2-0.3x+1=0 are x=-(3+sqrt(89))/4 ,x=(sqrt(89)-3)/4