What are the solutions to the equation x(2x-4)=(x-2)(x-2) ?

The solutions to the equation x(2x-4)=(x-2)(x-2) are x=2,x=-2

Find the zeros of x(2x-4)=(x-2)(x-2)

The zeros of x(2x-4)=(x-2)(x-2) are x=2,x=-2

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x (2 x - 4) = (x - 2) (x - 2)

x = 2, x = - 2

Solution steps

x (2 x - 4) = (x - 2) (x - 2)

Move

(x - 2) (x - 2)

to the left side

x (2 x - 4) - (x - 2) (x - 2) = 0

Factor

x (2 x - 4) - (x - 2) (x - 2) : (x - 2) (x + 2)

(x - 2) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = 2, x = - 2

3 x^{2} - 1 = 3 - 2 x^{2}

(3 x + 2) (2 x - 1) = 0

0.3 x^{2} + 0.4 x - 1 = 0

36 x^{2} - 4964 = 0

5 x^{2} - 8 x - 24 = 0

What are the solutions to the equation x(2x-4)=(x-2)(x-2) ?
The solutions to the equation x(2x-4)=(x-2)(x-2) are x=2,x=-2
Find the zeros of x(2x-4)=(x-2)(x-2)
The zeros of x(2x-4)=(x-2)(x-2) are x=2,x=-2