What are the solutions to the equation 3x^2-1=3-2x^2 ?

The solutions to the equation 3x^2-1=3-2x^2 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

Find the zeros of 3x^2-1=3-2x^2

The zeros of 3x^2-1=3-2x^2 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

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3 x^{2} - 1 = 3 - 2 x^{2}

x = \frac{2}{5}, x = - \frac{2}{5}

Decimal Notation

x = 0.89442 \dots, x = - 0.89442 \dots

Solution steps

3 x^{2} - 1 = 3 - 2 x^{2}

Move

1

to the right side

3 x^{2} = - 2 x^{2} + 4

Move

2 x^{2}

to the left side

5 x^{2} = 4

Divide both sides by

5

x^{2} = \frac{4}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{5}, x = - \frac{4}{5}

\frac{4}{5} = \frac{2}{5}

- \frac{4}{5} = - \frac{2}{5}

x = \frac{2}{5}, x = - \frac{2}{5}

(3 x + 2) (2 x - 1) = 0

0.3 x^{2} + 0.4 x - 1 = 0

36 x^{2} - 4964 = 0

5 x^{2} - 8 x - 24 = 0

x (x + 5) = 12

What are the solutions to the equation 3x^2-1=3-2x^2 ?
The solutions to the equation 3x^2-1=3-2x^2 are x= 2/(sqrt(5)),x=-2/(sqrt(5))
Find the zeros of 3x^2-1=3-2x^2
The zeros of 3x^2-1=3-2x^2 are x= 2/(sqrt(5)),x=-2/(sqrt(5))