What are the solutions to the equation (3x+2)(2x-1)=0 ?

The solutions to the equation (3x+2)(2x-1)=0 are x=-2/3 ,x= 1/2

Find the zeros of (3x+2)(2x-1)=0

The zeros of (3x+2)(2x-1)=0 are x=-2/3 ,x= 1/2

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(3 x + 2) (2 x - 1) = 0

x = - \frac{2}{3}, x = \frac{1}{2}

Decimal Notation

x = - 0.66666 \dots, x = 0.5

Solution steps

(3 x + 2) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or 2 x - 1 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = \frac{1}{2}

0.3 x^{2} + 0.4 x - 1 = 0

36 x^{2} - 4964 = 0

5 x^{2} - 8 x - 24 = 0

x (x + 5) = 12

x^{2} - 6 x - 160 = 0

What are the solutions to the equation (3x+2)(2x-1)=0 ?
The solutions to the equation (3x+2)(2x-1)=0 are x=-2/3 ,x= 1/2
Find the zeros of (3x+2)(2x-1)=0
The zeros of (3x+2)(2x-1)=0 are x=-2/3 ,x= 1/2