What are the solutions to the equation 0.3x^2+0.4x-1=0 ?

The solutions to the equation 0.3x^2+0.4x-1=0 are x=(-2+sqrt(34))/3 ,x=-(2+sqrt(34))/3

Find the zeros of 0.3x^2+0.4x-1=0

The zeros of 0.3x^2+0.4x-1=0 are x=(-2+sqrt(34))/3 ,x=-(2+sqrt(34))/3

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0.3 x^{2} + 0.4 x - 1 = 0

x = \frac{- 2 + 34}{3}, x = - \frac{2 + 34}{3}

Decimal Notation

x = 1.27698 \dots, x = - 2.61031 \dots

Solution steps

0.3 x^{2} + 0.4 x - 1 = 0

Multiply both sides by

10

3 x^{2} + 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 10) = 234

x_{1, 2} = \frac{- 4 \pm 2 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 34}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 34}{2 \cdot 3}

x = \frac{- 4 + 2 34}{2 \cdot 3} : \frac{- 2 + 34}{3}

x = \frac{- 4 - 2 34}{2 \cdot 3} : - \frac{2 + 34}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 34}{3}, x = - \frac{2 + 34}{3}

36 x^{2} - 4964 = 0

5 x^{2} - 8 x - 24 = 0

x (x + 5) = 12

x^{2} - 6 x - 160 = 0

x^{2} + 3 = 100

What are the solutions to the equation 0.3x^2+0.4x-1=0 ?
The solutions to the equation 0.3x^2+0.4x-1=0 are x=(-2+sqrt(34))/3 ,x=-(2+sqrt(34))/3
Find the zeros of 0.3x^2+0.4x-1=0
The zeros of 0.3x^2+0.4x-1=0 are x=(-2+sqrt(34))/3 ,x=-(2+sqrt(34))/3