What are the solutions to the equation (11x-1)^2-2(11x-1)-3=0 ?

The solutions to the equation (11x-1)^2-2(11x-1)-3=0 are x= 4/11 ,x=0

Find the zeros of (11x-1)^2-2(11x-1)-3=0

The zeros of (11x-1)^2-2(11x-1)-3=0 are x= 4/11 ,x=0

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(11 x - 1)^{2} - 2 (11 x - 1) - 3 = 0

x = \frac{4}{11}, x = 0

Decimal Notation

x = 0.36363 \dots, x = 0

Solution steps

(11 x - 1)^{2} - 2 (11 x - 1) - 3 = 0

Expand

(11 x - 1)^{2} - 2 (11 x - 1) - 3 : 121 x^{2} - 44 x

121 x^{2} - 44 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 44 ) \pm ( - 44 ) ^{2} - 4 \cdot 121 \cdot 0}{2 \cdot 121}

(- 44)^{2} - 4 \cdot 121 \cdot 0 = 44

x_{1, 2} = \frac{- ( - 44 ) \pm 44}{2 \cdot 121}

Separate the solutions

x_{1} = \frac{- ( - 44 ) + 44}{2 \cdot 121}, x_{2} = \frac{- ( - 44 ) - 44}{2 \cdot 121}

x = \frac{- ( - 44 ) + 44}{2 \cdot 121} : \frac{4}{11}

x = \frac{- ( - 44 ) - 44}{2 \cdot 121} : 0

The solutions to the quadratic equation are:

x = \frac{4}{11}, x = 0

26 t^{2} - 355 t + 300 = 0

10 x^{2} + 24 x - 130 = 0

x^{2} - 3 x + 4 = 2 x^{2} - 7 x - 8

(1 - x) (10 - x) - 9 = 0

(2 x + 4)^{2} = 5

What are the solutions to the equation (11x-1)^2-2(11x-1)-3=0 ?
The solutions to the equation (11x-1)^2-2(11x-1)-3=0 are x= 4/11 ,x=0
Find the zeros of (11x-1)^2-2(11x-1)-3=0
The zeros of (11x-1)^2-2(11x-1)-3=0 are x= 4/11 ,x=0