What are the solutions to the equation 26t^2-355t+300=0 ?

The solutions to the equation 26t^2-355t+300=0 are t=(355+5sqrt(3793))/(52),t=(355-5sqrt(3793))/(52)

Find the zeros of 26t^2-355t+300=0

The zeros of 26t^2-355t+300=0 are t=(355+5sqrt(3793))/(52),t=(355-5sqrt(3793))/(52)

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26 t^{2} - 355 t + 300 = 0

t = \frac{355 + 5 3793}{52}, t = \frac{355 - 5 3793}{52}

Decimal Notation

t = 12.74878 \dots, t = 0.90506 \dots

Solution steps

26 t^{2} - 355 t + 300 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 355 ) \pm ( - 355 ) ^{2} - 4 \cdot 26 \cdot 300}{2 \cdot 26}

(- 355)^{2} - 4 \cdot 26 \cdot 300 = 53793

t_{1, 2} = \frac{- ( - 355 ) \pm 5 3793}{2 \cdot 26}

Separate the solutions

t_{1} = \frac{- ( - 355 ) + 5 3793}{2 \cdot 26}, t_{2} = \frac{- ( - 355 ) - 5 3793}{2 \cdot 26}

t = \frac{- ( - 355 ) + 5 3793}{2 \cdot 26} : \frac{355 + 5 3793}{52}

t = \frac{- ( - 355 ) - 5 3793}{2 \cdot 26} : \frac{355 - 5 3793}{52}

The solutions to the quadratic equation are:

t = \frac{355 + 5 3793}{52}, t = \frac{355 - 5 3793}{52}

10 x^{2} + 24 x - 130 = 0

x^{2} - 3 x + 4 = 2 x^{2} - 7 x - 8

(1 - x) (10 - x) - 9 = 0

(2 x + 4)^{2} = 5

49 x^{2} + 1 = 25

What are the solutions to the equation 26t^2-355t+300=0 ?
The solutions to the equation 26t^2-355t+300=0 are t=(355+5sqrt(3793))/(52),t=(355-5sqrt(3793))/(52)
Find the zeros of 26t^2-355t+300=0
The zeros of 26t^2-355t+300=0 are t=(355+5sqrt(3793))/(52),t=(355-5sqrt(3793))/(52)