What are the solutions to the equation (2x-8)(2x+8)=55 ?

The solutions to the equation (2x-8)(2x+8)=55 are x=(sqrt(119))/2 ,x=-(sqrt(119))/2

Find the zeros of (2x-8)(2x+8)=55

The zeros of (2x-8)(2x+8)=55 are x=(sqrt(119))/2 ,x=-(sqrt(119))/2

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(2 x - 8) (2 x + 8) = 55

x = \frac{119}{2}, x = - \frac{119}{2}

Decimal Notation

x = 5.45435 \dots, x = - 5.45435 \dots

Solution steps

(2 x - 8) (2 x + 8) = 55

Expand

(2 x - 8) (2 x + 8) : 4 x^{2} - 64

4 x^{2} - 64 = 55

Move

55

to the left side

4 x^{2} - 119 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 4 ( - 119 )}{2 \cdot 4}

0^{2} - 4 \cdot 4 (- 119) = 4119

x_{1, 2} = \frac{- 0 \pm 4 119}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 0 + 4 119}{2 \cdot 4}, x_{2} = \frac{- 0 - 4 119}{2 \cdot 4}

x = \frac{- 0 + 4 119}{2 \cdot 4} : \frac{119}{2}

x = \frac{- 0 - 4 119}{2 \cdot 4} : - \frac{119}{2}

The solutions to the quadratic equation are:

x = \frac{119}{2}, x = - \frac{119}{2}

t^{2} + 8 t + 16 = 0

0 = 0.03 q^{2} + 35 q - 712

4 x^{2} - 250 = 0

4 x^{2} - 6 = 2 x

9 = - 4.9 t^{2} + 17.4 t + 2

What are the solutions to the equation (2x-8)(2x+8)=55 ?
The solutions to the equation (2x-8)(2x+8)=55 are x=(sqrt(119))/2 ,x=-(sqrt(119))/2
Find the zeros of (2x-8)(2x+8)=55
The zeros of (2x-8)(2x+8)=55 are x=(sqrt(119))/2 ,x=-(sqrt(119))/2