What are the solutions to the equation x^2+6x+9=2x(x+7) ?

The solutions to the equation x^2+6x+9=2x(x+7) are x=-9,x=1

Find the zeros of x^2+6x+9=2x(x+7)

The zeros of x^2+6x+9=2x(x+7) are x=-9,x=1

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x^{2} + 6 x + 9 = 2 x (x + 7)

x = - 9, x = 1

Solution steps

x^{2} + 6 x + 9 = 2 x (x + 7)

Expand

2 x (x + 7) : 2 x^{2} + 14 x

x^{2} + 6 x + 9 = 2 x^{2} + 14 x

Move

14 x

to the left side

x^{2} - 8 x + 9 = 2 x^{2}

Move

2 x^{2}

to the left side

- x^{2} - 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) \cdot 9}{2 ( - 1 )}

(- 8)^{2} - 4 (- 1) \cdot 9 = 10

x_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 10}{2 ( - 1 )}, x_{2} = \frac{- ( - 8 ) - 10}{2 ( - 1 )}

x = \frac{- ( - 8 ) + 10}{2 ( - 1 )} : - 9

x = \frac{- ( - 8 ) - 10}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 9, x = 1

4 x^{2} - 16 x - 48

(x - 4)^{2} - 25 = 12

(x + 7)^{2} - 288 = 0

5 x^{2} - 23 x = - 12

4 x^{2} - 4 x + 7 x - 7 = 2

What are the solutions to the equation x^2+6x+9=2x(x+7) ?
The solutions to the equation x^2+6x+9=2x(x+7) are x=-9,x=1
Find the zeros of x^2+6x+9=2x(x+7)
The zeros of x^2+6x+9=2x(x+7) are x=-9,x=1