What are the solutions to the equation (2x-7)(x+9)=0 ?

The solutions to the equation (2x-7)(x+9)=0 are x= 7/2 ,x=-9

Find the zeros of (2x-7)(x+9)=0

The zeros of (2x-7)(x+9)=0 are x= 7/2 ,x=-9

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(2 x - 7) (x + 9) = 0

x = \frac{7}{2}, x = - 9

Decimal Notation

x = 3.5, x = - 9

Solution steps

(2 x - 7) (x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 7 = 0 or x + 9 = 0

Solve

2 x - 7 = 0 : x = \frac{7}{2}

Solve

x + 9 = 0 : x = - 9

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 9

x, 3 y - 6 = 12 x^{2} - 6 y^{3}

9 x^{2} + 24 x - 24 = 0

6 x^{2} - 13 x - 28 = 0

6 x^{2} + 2 x - 18 = 0

16 x^{2} - 4 = 4 x^{2} + \frac{3}{4}

What are the solutions to the equation (2x-7)(x+9)=0 ?
The solutions to the equation (2x-7)(x+9)=0 are x= 7/2 ,x=-9
Find the zeros of (2x-7)(x+9)=0
The zeros of (2x-7)(x+9)=0 are x= 7/2 ,x=-9