What are the solutions to the equation 9x^2+24x-24=0 ?

The solutions to the equation 9x^2+24x-24=0 are x=(2(sqrt(10)-2))/3 ,x=-(2(2+sqrt(10)))/3

Find the zeros of 9x^2+24x-24=0

The zeros of 9x^2+24x-24=0 are x=(2(sqrt(10)-2))/3 ,x=-(2(2+sqrt(10)))/3

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9 x^{2} + 24 x - 24 = 0

x = \frac{2 ( 10 - 2 )}{3}, x = - \frac{2 ( 2 + 10 )}{3}

Decimal Notation

x = 0.77485 \dots, x = - 3.44151 \dots

Solution steps

9 x^{2} + 24 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 ( - 24 )}{2 \cdot 9}

2 4^{2} - 4 \cdot 9 (- 24) = 1210

x_{1, 2} = \frac{- 24 \pm 12 10}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 24 + 12 10}{2 \cdot 9}, x_{2} = \frac{- 24 - 12 10}{2 \cdot 9}

x = \frac{- 24 + 12 10}{2 \cdot 9} : \frac{2 ( 10 - 2 )}{3}

x = \frac{- 24 - 12 10}{2 \cdot 9} : - \frac{2 ( 2 + 10 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 10 - 2 )}{3}, x = - \frac{2 ( 2 + 10 )}{3}

6 x^{2} - 13 x - 28 = 0

6 x^{2} + 2 x - 18 = 0

16 x^{2} - 4 = 4 x^{2} + \frac{3}{4}

2 x^{2} - 8 x + 13

x^{2} - 6 x = - 10 x + 12

What are the solutions to the equation 9x^2+24x-24=0 ?
The solutions to the equation 9x^2+24x-24=0 are x=(2(sqrt(10)-2))/3 ,x=-(2(2+sqrt(10)))/3
Find the zeros of 9x^2+24x-24=0
The zeros of 9x^2+24x-24=0 are x=(2(sqrt(10)-2))/3 ,x=-(2(2+sqrt(10)))/3