What are the solutions to the equation 4x^2-16x-20=0 ?

The solutions to the equation 4x^2-16x-20=0 are x=5,x=-1

Find the zeros of 4x^2-16x-20=0

The zeros of 4x^2-16x-20=0 are x=5,x=-1

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4 x^{2} - 16 x - 20 = 0

x = 5, x = - 1

Solution steps

4 x^{2} - 16 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 ( - 20 )}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 (- 20) = 24

x_{1, 2} = \frac{- ( - 16 ) \pm 24}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 24}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 24}{2 \cdot 4}

x = \frac{- ( - 16 ) + 24}{2 \cdot 4} : 5

x = \frac{- ( - 16 ) - 24}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

3 q^{2} - 110 q + 900 = 0

(x - 2) (x + 3) = 2 x^{2} - 4 x

9 x^{2} - 9 x + 19 = 0

x^{2} + 2 x - 12 = - 12

4 x^{2} + 17 x + 17 = 1

What are the solutions to the equation 4x^2-16x-20=0 ?
The solutions to the equation 4x^2-16x-20=0 are x=5,x=-1
Find the zeros of 4x^2-16x-20=0
The zeros of 4x^2-16x-20=0 are x=5,x=-1