What are the solutions to the equation x^2+2x-12=-12 ?

The solutions to the equation x^2+2x-12=-12 are x=0,x=-2

Find the zeros of x^2+2x-12=-12

The zeros of x^2+2x-12=-12 are x=0,x=-2

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x^{2} + 2 x - 12 = - 12

x = 0, x = - 2

Solution steps

x^{2} + 2 x - 12 = - 12

Move

12

to the left side

x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 2}{2 \cdot 1}

x = \frac{- 2 + 2}{2 \cdot 1} : 0

x = \frac{- 2 - 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

4 x^{2} + 17 x + 17 = 1

mn x^{2} = mn - (m^{2} - n^{2}) x

x^{2} + 3 x - 0.9 = 0

4.905 x^{2} - 90 x - 150 = 0

x^{2} - 10 x + 25 = 0

What are the solutions to the equation x^2+2x-12=-12 ?
The solutions to the equation x^2+2x-12=-12 are x=0,x=-2
Find the zeros of x^2+2x-12=-12
The zeros of x^2+2x-12=-12 are x=0,x=-2