What are the solutions to the equation 3q^2-110q+900=0 ?

The solutions to the equation 3q^2-110q+900=0 are q=(5(11+sqrt(13)))/3 ,q=(5(11-sqrt(13)))/3

Find the zeros of 3q^2-110q+900=0

The zeros of 3q^2-110q+900=0 are q=(5(11+sqrt(13)))/3 ,q=(5(11-sqrt(13)))/3

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3 q^{2} - 110 q + 900 = 0

q = \frac{5 ( 11 + 13 )}{3}, q = \frac{5 ( 11 - 13 )}{3}

Decimal Notation

q = 24.34258 \dots, q = 12.32408 \dots

Solution steps

3 q^{2} - 110 q + 900 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 110 ) \pm ( - 110 ) ^{2} - 4 \cdot 3 \cdot 900}{2 \cdot 3}

(- 110)^{2} - 4 \cdot 3 \cdot 900 = 1013

q_{1, 2} = \frac{- ( - 110 ) \pm 10 13}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- ( - 110 ) + 10 13}{2 \cdot 3}, q_{2} = \frac{- ( - 110 ) - 10 13}{2 \cdot 3}

q = \frac{- ( - 110 ) + 10 13}{2 \cdot 3} : \frac{5 ( 11 + 13 )}{3}

q = \frac{- ( - 110 ) - 10 13}{2 \cdot 3} : \frac{5 ( 11 - 13 )}{3}

The solutions to the quadratic equation are:

q = \frac{5 ( 11 + 13 )}{3}, q = \frac{5 ( 11 - 13 )}{3}

(x - 2) (x + 3) = 2 x^{2} - 4 x

9 x^{2} - 9 x + 19 = 0

x^{2} + 2 x - 12 = - 12

4 x^{2} + 17 x + 17 = 1

mn x^{2} = mn - (m^{2} - n^{2}) x

What are the solutions to the equation 3q^2-110q+900=0 ?
The solutions to the equation 3q^2-110q+900=0 are q=(5(11+sqrt(13)))/3 ,q=(5(11-sqrt(13)))/3
Find the zeros of 3q^2-110q+900=0
The zeros of 3q^2-110q+900=0 are q=(5(11+sqrt(13)))/3 ,q=(5(11-sqrt(13)))/3