What are the solutions to the equation x^2-5x=2x^2+x ?

The solutions to the equation x^2-5x=2x^2+x are x=-6,x=0

Find the zeros of x^2-5x=2x^2+x

The zeros of x^2-5x=2x^2+x are x=-6,x=0

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x^{2} - 5 x = 2 x^{2} + x

x = - 6, x = 0

Solution steps

x^{2} - 5 x = 2 x^{2} + x

Move

x

to the left side

x^{2} - 6 x = 2 x^{2}

Move

2 x^{2}

to the left side

- x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 6}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 6}{2 ( - 1 )} : - 6

x = \frac{- ( - 6 ) - 6}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

x = - 6, x = 0

\frac{x ^{2}}{3} - 8 x - 18 = 0

2 c^{2} + 4 c - 6 = - 3 c

y^{2} - 10 y = - 21

12 x^{2} - 38 x - 10 = 0

s^{2} + 4 s + 9 = 0

What are the solutions to the equation x^2-5x=2x^2+x ?
The solutions to the equation x^2-5x=2x^2+x are x=-6,x=0
Find the zeros of x^2-5x=2x^2+x
The zeros of x^2-5x=2x^2+x are x=-6,x=0