What are the solutions to the equation (x^2)/3-8x-18=0 ?

The solutions to the equation (x^2)/3-8x-18=0 are x=3(4+sqrt(22)),x=3(4-sqrt(22))

Find the zeros of (x^2)/3-8x-18=0

The zeros of (x^2)/3-8x-18=0 are x=3(4+sqrt(22)),x=3(4-sqrt(22))

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\frac{x ^{2}}{3} - 8 x - 18 = 0

x = 3 (4 + 22), x = 3 (4 - 22)

Decimal Notation

x = 26.07124 \dots, x = - 2.07124 \dots

Solution steps

\frac{x ^{2}}{3} - 8 x - 18 = 0

Multiply both sides by

3

x^{2} - 24 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot (- 54) = 622

x_{1, 2} = \frac{- ( - 24 ) \pm 6 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 6 22}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 6 22}{2 \cdot 1}

x = \frac{- ( - 24 ) + 6 22}{2 \cdot 1} : 3 (4 + 22)

x = \frac{- ( - 24 ) - 6 22}{2 \cdot 1} : 3 (4 - 22)

The solutions to the quadratic equation are:

x = 3 (4 + 22), x = 3 (4 - 22)

2 c^{2} + 4 c - 6 = - 3 c

y^{2} - 10 y = - 21

12 x^{2} - 38 x - 10 = 0

s^{2} + 4 s + 9 = 0

x^{2} + 5 x + 2 = - 4

What are the solutions to the equation (x^2)/3-8x-18=0 ?
The solutions to the equation (x^2)/3-8x-18=0 are x=3(4+sqrt(22)),x=3(4-sqrt(22))
Find the zeros of (x^2)/3-8x-18=0
The zeros of (x^2)/3-8x-18=0 are x=3(4+sqrt(22)),x=3(4-sqrt(22))