What are the solutions to the equation y^2-10y=-21 ?

The solutions to the equation y^2-10y=-21 are y=7,y=3

Find the zeros of y^2-10y=-21

The zeros of y^2-10y=-21 are y=7,y=3

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y^{2} - 10 y = - 21

y = 7, y = 3

Solution steps

y^{2} - 10 y = - 21

Move

21

to the left side

y^{2} - 10 y + 21 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 21 = 4

y_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 1}

y = \frac{- ( - 10 ) + 4}{2 \cdot 1} : 7

y = \frac{- ( - 10 ) - 4}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

y = 7, y = 3

12 x^{2} - 38 x - 10 = 0

s^{2} + 4 s + 9 = 0

x^{2} + 5 x + 2 = - 4

\frac{( x - 2 ) ^{2}}{2} = x + 2

x^{2} - 2 x + 4 = 0

What are the solutions to the equation y^2-10y=-21 ?
The solutions to the equation y^2-10y=-21 are y=7,y=3
Find the zeros of y^2-10y=-21
The zeros of y^2-10y=-21 are y=7,y=3