What are the solutions to the equation x^2-8x+45=0 ?

The solutions to the equation x^2-8x+45=0 are x=4+sqrt(29)i,x=4-sqrt(29)i

Find the zeros of x^2-8x+45=0

The zeros of x^2-8x+45=0 are x=4+sqrt(29)i,x=4-sqrt(29)i

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x^{2} - 8 x + 45 = 0

x = 4 + 29 i, x = 4 - 29 i

Solution steps

x^{2} - 8 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 45 : 229 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 29 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 29 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 29 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 29 i}{2 \cdot 1} : 4 + 29 i

x = \frac{- ( - 8 ) - 2 29 i}{2 \cdot 1} : 4 - 29 i

The solutions to the quadratic equation are:

x = 4 + 29 i, x = 4 - 29 i

x^{2} + 7 x - 18 = 0

81 x^{2} - 180 x + 100 = 100

x^{2} + 3 x = - 9 - 3 x

9 x^{2} + 24 x + 17 = 0

6 (x^{2} - 2) = 3 (x^{2} + 1)

What are the solutions to the equation x^2-8x+45=0 ?
The solutions to the equation x^2-8x+45=0 are x=4+sqrt(29)i,x=4-sqrt(29)i
Find the zeros of x^2-8x+45=0
The zeros of x^2-8x+45=0 are x=4+sqrt(29)i,x=4-sqrt(29)i