What are the solutions to the equation 81x^2-180x+100=100 ?

The solutions to the equation 81x^2-180x+100=100 are x= 20/9 ,x=0

Find the zeros of 81x^2-180x+100=100

The zeros of 81x^2-180x+100=100 are x= 20/9 ,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

81 x^{2} - 180 x + 100 = 100

x = \frac{20}{9}, x = 0

Decimal Notation

x = 2.22222 \dots, x = 0

Solution steps

81 x^{2} - 180 x + 100 = 100

Move

100

to the left side

81 x^{2} - 180 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 180 ) \pm ( - 180 ) ^{2} - 4 \cdot 81 \cdot 0}{2 \cdot 81}

(- 180)^{2} - 4 \cdot 81 \cdot 0 = 180

x_{1, 2} = \frac{- ( - 180 ) \pm 180}{2 \cdot 81}

Separate the solutions

x_{1} = \frac{- ( - 180 ) + 180}{2 \cdot 81}, x_{2} = \frac{- ( - 180 ) - 180}{2 \cdot 81}

x = \frac{- ( - 180 ) + 180}{2 \cdot 81} : \frac{20}{9}

x = \frac{- ( - 180 ) - 180}{2 \cdot 81} : 0

The solutions to the quadratic equation are:

x = \frac{20}{9}, x = 0

x^{2} + 3 x = - 9 - 3 x

9 x^{2} + 24 x + 17 = 0

6 (x^{2} - 2) = 3 (x^{2} + 1)

x (x + 2) = 120

x, \frac{x ^{2}}{18} = r

What are the solutions to the equation 81x^2-180x+100=100 ?
The solutions to the equation 81x^2-180x+100=100 are x= 20/9 ,x=0
Find the zeros of 81x^2-180x+100=100
The zeros of 81x^2-180x+100=100 are x= 20/9 ,x=0