What are the solutions to the equation x^2+3x=-9-3x ?

The solutions to the equation x^2+3x=-9-3x are x=-3

Find the zeros of x^2+3x=-9-3x

The zeros of x^2+3x=-9-3x are x=-3

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x^{2} + 3 x = - 9 - 3 x

x = - 3

Solution steps

x^{2} + 3 x = - 9 - 3 x

Move

3 x

to the left side

x^{2} + 6 x = - 9

Move

9

to the left side

x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

x = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

9 x^{2} + 24 x + 17 = 0

6 (x^{2} - 2) = 3 (x^{2} + 1)

x (x + 2) = 120

x, \frac{x ^{2}}{18} = r

s^{2} + 2 s + 20 = 0

What are the solutions to the equation x^2+3x=-9-3x ?
The solutions to the equation x^2+3x=-9-3x are x=-3
Find the zeros of x^2+3x=-9-3x
The zeros of x^2+3x=-9-3x are x=-3